CBSE · Class 11 · Physics · Mechanical Properties of FluidsHow does the terminal velocity ($vt$) of a small spherical body falling through a viscous fluid depend on its radius ($r$)?
Step-by-Step Solution
According to Stokes' Law, terminal velocity is given by $v_t = \frac{2}{9}\frac{r^2(\rho - \sigma)g}{\neta}$. Therefore, $v_t \propto r^2$.
Detailed Options Breakdown
Option : $v_t \propto r^2$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: $v_t \propto r$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Mechanical Properties of Fluids.
Option 2: $v_t \propto 1/r$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Mechanical Properties of Fluids.
Option 3: $v_t \propto r^3$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Mechanical Properties of Fluids.
💡 Study Guide: This question tests core syllabus concepts from Mechanical Properties of Fluids. For formulas, key summaries, and mock exam reference guides, read the full Mechanical Properties of Fluids Revision Notes.