CBSE · Class 11 · Physics · Kinetic TheoryAt what temperature does the root mean square (RMS) speed of gas molecules theoretically become zero?
Step-by-Step Solution
Since $v_{rms} = \sqrt{\frac{3RT}{M}}$, $v_{rms}$ becomes zero when the absolute temperature $T = 0\text{ K}$ (Absolute Zero).
Detailed Options Breakdown
Option : $0^\circ\text{C}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Kinetic Theory.
Option 1: $273\text{ K}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Kinetic Theory.
Option 2: $0\text{ K}$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 3: $-100^\circ\text{C}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Kinetic Theory.
💡 Study Guide: This question tests core syllabus concepts from Kinetic Theory. For formulas, key summaries, and mock exam reference guides, read the full Kinetic Theory Revision Notes.