CBSE · Class 11 · Physics · Kinetic TheoryWhich of the following correct relationship exists between RMS speed ($v{rms}$), average speed ($v{avg}$), and most probable speed ($v{mp}$) of gas molecules?
Step-by-Step Solution
$v_{rms} = \sqrt{\frac{3RT}{M}} \approx 1.732 \sqrt{\frac{RT}{M}}$, $v_{avg} = \sqrt{\frac{8RT}{\pi M}} \approx 1.596 \sqrt{\frac{RT}{M}}$, $v_{mp} = \sqrt{\frac{2RT}{M}} \approx 1.414 \sqrt{\frac{RT}{M}}$. Therefore, $v_{rms} > v_{avg} > v_{mp}$.
Detailed Options Breakdown
Option : $v_{mp} > v_{avg} > v_{rms}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Kinetic Theory.
Option 1: $v_{rms} > v_{avg} > v_{mp}$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: $v_{avg} > v_{rms} > v_{mp}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Kinetic Theory.
Option 3: $v_{rms} = v_{avg} = v_{mp}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Kinetic Theory.
💡 Study Guide: This question tests core syllabus concepts from Kinetic Theory. For formulas, key summaries, and mock exam reference guides, read the full Kinetic Theory Revision Notes.