MCQPhysics

CBSE · Class 11 · Physics · GravitationAt what place on the Earth's surface is the value of acceleration due to gravity ($g$) maximum?

Step-by-Step Solution

Due to Earth's shape (flattened at poles) and rotation ($ g_{\phi} = g - \omega^2 R \cos^2 \phi$), $g$ is maximum at the poles ($ \phi = 90^\circ$).

Detailed Options Breakdown
Option : At the Equator

Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.

Option 1: At the Poles (Correct Answer)

Correct choice. Refer to the step-by-step verified solution guidelines above for details.

Option 2: At latitude $45^\circ$

Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.

Option 3: Same everywhere

Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.

💡 Study Guide: This question tests core syllabus concepts from Gravitation. For formulas, key summaries, and mock exam reference guides, read the full Gravitation Revision Notes.
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