CBSE · Class 11 · Mathematics · ProbabilityIf $P(A) = \frac{3}{5}$ and $P(B) = \frac{1}{5}$, find $P(A \cup B)$ if $A$ and $B$ are mutually exclusive events.
Step-by-Step Solution
For mutually exclusive events, $P(A \cap B) = 0$. The addition theorem of probability states that $P(A \cup B) = P(A) + P(B) - P(A \cap B)$. Substituting the given values, we get $P(A \cup B) = \frac{3}{5} + \frac{1}{5} - 0 = \frac{4}{5}$. Thus, the correct option is $\frac{4}{5}$.
Detailed Options Breakdown
Option : 1/5
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Probability.
Option 1: 2/5
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Probability.
Option 2: 4/5 (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 3: 3/25
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Probability.
💡 Study Guide: This question tests core syllabus concepts from Probability. For formulas, key summaries, and mock exam reference guides, read the full Probability Revision Notes.