CBSE · Class 11 · Mathematics · Complex Numbers and Quadratic EquationsWhat is the multiplicative inverse of $2 - 3i$?
Step-by-Step Solution
The multiplicative inverse of a complex number $z = a + ib$ is given by $\bar{z} / |z|^2$. For $z = 2 - 3i$, the conjugate is $\bar{z} = 2 + 3i$ and $|z|^2 = 2^2 + (-3)^2 = 4 + 9 = 13$. Therefore, the multiplicative inverse is $(2 + 3i) / 13$.
Detailed Options Breakdown
Option : \frac{2+3i}{13} (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: \frac{2-3i}{13}
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Complex Numbers and Quadratic Equations.
Option 2: \frac{2+3i}{5}
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Complex Numbers and Quadratic Equations.
Option 3: 2 + 3i
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Complex Numbers and Quadratic Equations.
💡 Study Guide: This question tests core syllabus concepts from Complex Numbers and Quadratic Equations. For formulas, key summaries, and mock exam reference guides, read the full Complex Numbers and Quadratic Equations Revision Notes.