CBSE · Class 11 · Mathematics · Binomial TheoremIf ${}^{n}C{8} = {}^{n}C{2}$, what is the value of $n$?
Step-by-Step Solution
We know that ${}^{n}C_{x} = {}^{n}C_{y}$ implies either $x = y$ or $x + y = n$. Since $8 \neq 2$, we must have $8 + 2 = n$, which gives $n = 10$.
Detailed Options Breakdown
Option : $6$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Binomial Theorem.
Option 1: $8$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Binomial Theorem.
Option 2: $10$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 3: $16$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Binomial Theorem.
💡 Study Guide: This question tests core syllabus concepts from Binomial Theorem. For formulas, key summaries, and mock exam reference guides, read the full Binomial Theorem Revision Notes.