CBSE · Class 11 · Mathematics · Binomial TheoremWhat is the value of ${}^{n}C{0}$?
Step-by-Step Solution
By definition, ${}^{n}C_{r} = \frac{n!}{r!(n-r)!}$. Substituting $r = 0$, we get ${}^{n}C_{0} = \frac{n!}{0!n!} = 1$.
Detailed Options Breakdown
Option : $0$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Binomial Theorem.
Option 1: $1$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: $n$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Binomial Theorem.
Option 3: Undefined
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Binomial Theorem.
💡 Study Guide: This question tests core syllabus concepts from Binomial Theorem. For formulas, key summaries, and mock exam reference guides, read the full Binomial Theorem Revision Notes.