CBSE · Class 11 · Chemistry · Structure of AtomWhat is the energy of an electron in the first Bohr orbit of Hydrogen atom?
Step-by-Step Solution
Energy formula for H-atom is $E_n = -\frac{13.6}{n^2} \text{ eV}$. For $n=1$, $E_1 = -13.6 \text{ eV}$ (or $-2.18 \times 10^{-18} \text{ J}$).
Detailed Options Breakdown
Option : $-13.6 \text{ eV}$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: $-3.4 \text{ eV}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Structure of Atom.
Option 2: $-1.51 \text{ eV}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Structure of Atom.
Option 3: $0 \text{ eV}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Structure of Atom.
💡 Study Guide: This question tests core syllabus concepts from Structure of Atom. For formulas, key summaries, and mock exam reference guides, read the full Structure of Atom Revision Notes.