CBSE · Class 11 · Chemistry · EquilibriumWhat is the pH of a $10^{-3} \text{ M } HCl$ solution at $298 \text{ K}$?
Step-by-Step Solution
$HCl$ is a strong acid, so $[H^+] = 10^{-3} \text{ M}$. $pH = -\log[H^+] = -\log(10^{-3}) = 3$.
Detailed Options Breakdown
Option : 1
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Equilibrium.
Option 1: 2
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Equilibrium.
Option 2: 3 (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 3: 11
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Equilibrium.
💡 Study Guide: This question tests core syllabus concepts from Equilibrium. For formulas, key summaries, and mock exam reference guides, read the full Equilibrium Revision Notes.