LAMathematics

CBSE · Class 10 · Mathematics · PolynomialsFind the value of x in the polynomial 2x^2 + 5x - 3, given that it has a root at x = 1.

Step-by-Step Solution

Step 1: Factorize the polynomial\nSince we know that x = 1 is a root of the polynomial, we can factorize the polynomial as:

2x^2 + 5x - 3 = (x - 1)(2x + 3)

Step 2: Use the factor theorem\nBy the factor theorem, we know that if (x - a) is a factor of a polynomial, then a is a root of the polynomial. In this case, we have:

(x - 1)(2x + 3) = 0\nThis implies that either (x - 1) = 0 or (2x + 3) = 0

Step 3: Solve for x\nSolving for x, we get:\nx - 1 = 0 --> x = 1

2x + 3 = 0 --> 2x = -3 --> x = -3/2

Conclusion\nTherefore, the value of x in the polynomial 2x^2 + 5x - 3 is x = -3/2.

💡 Study Guide: This question tests core syllabus concepts from Polynomials. For formulas, key summaries, and mock exam reference guides, read the full Polynomials Revision Notes.
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