CBSE · Class 10 · Mathematics · CirclesFrom a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm. The radius of the circle is:
Step-by-Step Solution
Using Pythagoras theorem in the right-angled triangle formed by the radius, tangent, and line from center to Q: Radius = $\sqrt{25^2 - 24^2} = \sqrt{625 - 576} = \sqrt{49} = 7$ cm.
Detailed Options Breakdown
Option : 7 cm (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: 12 cm
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Circles.
Option 2: 15 cm
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Circles.
Option 3: 24.5 cm
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Circles.
💡 Study Guide: This question tests core syllabus concepts from Circles. For formulas, key summaries, and mock exam reference guides, read the full Circles Revision Notes.