CBSE · Class 10 · Mathematics · Applications of TrigonometryThe angle of elevation of the sun when the shadow of a pole $h$ meters high is $\sqrt{3}h$ meters long is:
Let the angle of elevation of the sun be $\theta$. The height of the pole (opposite side) is $h$ and the length of the shadow (adjacent side) is $\sqrt{3}h$. Therefore, $\tan \theta = \frac{\text{Height}}{\text{Length of shadow}} = \frac{h}{\sqrt{3}h} = \frac{1}{\sqrt{3}}$. Since $\tan 30^\circ = \frac{1}{\sqrt{3}}$, we get $\theta = 30^\circ$.
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.